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2 carts are placed next to each other on a low-friction track. The carts are equipped with a spring-loaded mechanism which allows them to impart an impulse to each other. Cart A has a mass of M and Cart B has a mass of 6.4 x M. The spring-loaded mechanism is engaged and then released. The impulse causes Cart A to be propelled forward with a velocity of 42.6 m/s. The velocity of the Cart B right after the release will be

Respuesta :

[tex]\begin{gathered} Cart\text{ A} \\ m_A=M \\ v_A=42.6\text{ m/s} \\ Cart\text{ B} \\ m_B=6.4M \\ v_B=? \\ Impulse=Momentum \\ I=P \\ P=mv \\ P_A=P_B \\ m_Av_A=m_Bv_B \\ Solving\text{ vb} \\ v_B=\frac{m_Av_A}{m_B} \\ v_B=\frac{(M)(42.6m/s)}{6.4M} \\ v_{B=}6.7m/s \\ The\text{ velocity of the cart B is 6.7 m/s} \\ \\ \end{gathered}[/tex]

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