Transformation(s)f(x)-4x+5g(x)=-4x+7Reflection across y-axis, andshift up 2 unitsf(x)=1/3x-2g(x)=3(x+2)-2rotated counterclockwise, andshifted to the left by 2 unitsf(x)=-2/3x+16g(x)= 2/3(x-3) -16reflexed across the y-axis,shifted to the right by 3 units,f(x)=14(x-3)+1g(x)=7(x+2)+1f(x)-6(x+2)-3g(x)=8(x-3)+6f(x)=3(x-1)+?g(x)=3(3-X)-23f(x)=1/(x+2)-4g(x) = 3(-x-2)+62012first 3 are already done please don’t redo them.

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HiyabX656196 HiyabX656196 · Answer 1 · 2022-10-27T22:31:01+02:00

Given the transformation below

[tex]f(x)=14(x-3)+1\Rightarrow g(x)=7(x+2)+1[/tex]

The transformation is: Vertical compressed by 1/2, shifted left by 5.

Given the transformation below

[tex]f(x)=6(x+2)-3\Rightarrow g(x)=8(x-3)+6[/tex]

The transformation is: Vertical stretched by 4/3, shifted right by 9.

Given the transformation below

[tex]f(x)=3(x+1)+\frac{2}{3}\Rightarrow g(x)=3(3-x)-\frac{2}{3}[/tex]

The transformation is: Reflection over the y-axis, shifted left by 2, shifted downward by 4/3.

Given the transformation below

[tex]f(x)=-\frac{1}{3}(x+2)-4\Rightarrow g(x)=\frac{1}{3}(-x-2)+6[/tex]

The transformation is: Upward shift by 10units.

Given the transformation below

[tex]f(x)=\frac{4}{3}(x-\frac{2}{3})+\frac{1}{3}\Rightarrow g(x)=\frac{2}{3}(\frac{2}{3}-x)[/tex]

The transformation is: Vertical compression by 1/2, reflected over the y-axis, shifted download by 1/3.