SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Draw the scenario
STEP 2: Write the given values from the drawing above
[tex]\theta=32^{\circ},adjacent=40,opposite=x[/tex]
STEP 3: Solve for x using the appropriate trigonomentric ratio
[tex]\begin{gathered} \text{Given }\theta,adjacent\text{ and opposite, we use:} \\ \tan \theta=\frac{\text{opposite}}{\text{adjacent}} \\ \tan 32^{\circ}=\frac{x}{40} \\ By\text{ cross multiplication,} \\ x=40\times\tan 32^{\circ} \\ x=40\times0.624869351=24.99477408 \\ x\approx25\text{ f}eet\text{ to the nearest foot} \end{gathered}[/tex]
Hence, the height of the flagpole is approximately 25 feet
