To answer this question we will use the following formula for binomial probability:
[tex]P(x)=\binom{n}{x}p^x(1-p)^{n-x},[/tex]where x is the number of times for a specific outcome within n trials, and p is the probability of success on a single trial.
Substituting x=5, n=12, and p=0.44 in the above formula we get:
[tex]P(5)=\binom{12}{5}(0.44)^5(1-0.44)^{12-5}.[/tex]Simplifying the above result we get:
[tex]\begin{gathered} P(5)=\frac{12!}{5!(12-5)!}(0.44)^5(0.56)^7=792*0.44^5*0.56^7 \\ \approx0.226. \end{gathered}[/tex]Answer: 0.226.