The acceleration at the end of a test tube that is 10 cmfrom the axis of rotation is 17545.9m/[tex]s^{2}[/tex]
What is axis of rotation ?
The line drawn through all of a rotating rigid body's fixed points, around which all of the body's other points revolve.
The relation for the centripetal acceleration is:
ac=[tex]w^{2}[/tex]R
= 4[tex]\pi[/tex][tex]pi^{2} f^{2}[/tex]R
Where f is a frequency of rotation,
R –distance from axis of rotation to the end of the tube.
Numerically
ac=17545.9m/[tex]s^{2}[/tex]
Learn more about axis of rotation from given link
https://brainly.com/question/22283462
#SPJ4
