Pls help Applying the 30-60-90 special right triangle rules, find the value of x and y

Answer:
x = 10, y = 5
Step-by-step explanation:
The sine of 60 is given by the division of the opposite side of 60º by the hypothenuse.
We have that:
sine of 60 is sqrt(3)/2
The oopposite side is 5sqrt(3)
The hypothenuse is x.
So
[tex]\frac{\sqrt{3}}{2}=\frac{5\sqrt{3}}{x}[/tex]Then we apply cross multiplication.
[tex]\sqrt{3}x=2\ast5\sqrt{3}[/tex][tex]x=\frac{10\sqrt{3}}{\sqrt{3}}=10[/tex]The cosine of 60 is the adjacent side divided by the hypothenuse.
The cosine of 60 is 1/2.
The adjacent side is y.
The hypothenuse is x = 10. So
[tex]\frac{1}{2}=\frac{y}{10}[/tex]Applying cross multiplication
2y = 10
y = 5