Part (a)
The final speed of body can be expressed as,
[tex]v=u-gt[/tex]
Substitute the known values,
[tex]\begin{gathered} 58.8m/s=0m/s-(-9.8m/s^2)t \\ t=\frac{58.8\text{ m/s}}{9.8m/s^2} \\ =6.0\text{ s} \end{gathered}[/tex]
Thus, the time taken by body to acquire the final speed is 6.0 s.
Part (b)
The distance covered by the body can be given as,
[tex]d=ut-\frac{1}{2}gt^2[/tex]
Substitute the known values,
[tex]\begin{gathered} d=(0\text{ m/s)(6.0 s)-}\frac{1}{2}(-9.8m/s^2)(6.0s)^2 \\ =0\text{ m+}176.4\text{ m} \\ =176.4\text{ m} \end{gathered}[/tex]
Thus, the vertical distance covered by body is 176.4 m.
