we find the area of the figure
tent1: area rectangular figure
[tex]\begin{gathered} A=2wh+2lh \\ A=2(30\times8)+2(40\times8) \\ A=2(240)+2(320) \\ A=480+640 \\ A=1120 \end{gathered}[/tex]tent2: area rectangular pyramid
[tex]\begin{gathered} A=\frac{2lh}{2}+\frac{2wh}{2} \\ A=lh+wh \\ A=40\times12+30\times12 \\ A=480+360 \\ A=840 \end{gathered}[/tex]answer:
tent 1: 1120 sq feet
ten2: 840 sq feet