Respuesta :
We have a system of simultaneous equations and are required to solve via substitution.
We are simply asked to get x or y in terms of the other and substitute in the other equation to solve for the variable.
When solved, this found variable will be used to solve the other variable.
[tex]\begin{gathered} 4x+3y=5\ldots(1) \\ x=4y+6\ldots(2) \\ \text{ We substitute this value of x in eqn 2 in eqn 1 to get:} \\ 4(4y+6)+3y=5 \\ 16y+24+3y=5 \\ \text{ We subtract 24 from both sides of the equation to get:} \\ 19y=5-24=-19 \\ \text{ We divide both sides of the equation to get:} \\ y=-\frac{19}{19}=-1 \end{gathered}[/tex]Now we know y, we substitute this value of y into equation 1 to get:
[tex]\begin{gathered} 4x+3(-1)=5 \\ 4x-3=5 \\ \text{ We add 3 to both sides to get:} \\ 4x=5+3=8 \\ \text{ Divide both sides by }4\text{ to get:} \\ x=\frac{8}{4}=2 \end{gathered}[/tex]x = 2
y =-1
