Algebraically, 'eight times a number' is written 8x; on the other hand, 'three subtracted from eight times a number' is 8x-3. Therefore, the whole expression is
[tex]8x-3=85[/tex]
The answer to part A) is 8x-3=85
B) Solving the equation in part A) for x,
[tex]\begin{gathered} \Rightarrow8x=85+3=88 \\ \Rightarrow x=\frac{88}{8}=11 \\ \Rightarrow x=11 \end{gathered}[/tex]
The answer to part B) is x=11.
