SOLUTION
(1) From here we are told to use the formula
[tex]\begin{gathered} A(t)=A_o(1+\frac{r}{n})^{nt} \\ Where\text{ } \\ A_o=money\text{ invested = 2,000 dollars} \\ r=interest\text{ rate = 4.3\%= }\frac{4.3}{100}=\text{ 0.043} \\ n=number\text{ of compounding, quarterly = 4} \\ t=time\text{ in years = 5years } \end{gathered}[/tex]
Plugging the values into the formula, we have
[tex]\begin{gathered} A(t)=A_o(1+\frac{r}{n})^{nt} \\ A(t)=2,000(1+\frac{0.043}{4})^{4\times5} \\ A(t)=2,000(1+0.01075)^{20} \\ =2000(1.01075)^{20} \\ =2000\times1.23844 \\ =2476.880168 \\ =2476.88\text{ dollars } \end{gathered}[/tex]
Hence the answer is $2476.88
