Let the population after 10 years be p
Then
[tex]p=23850(1+0.03)^{10}[/tex][tex]\Rightarrow\text{ p=23850}\times1.03^{10}=32052[/tex]Hence the population after 10 years is 32052
Given an intial population of p0 with a growth rate of r% per year. Then in
n years. The new population p, will be given by
[tex]p=p_0(1+\frac{r}{100})^n[/tex]