Given,
The linear velocity of the pizza dough, v=0.65 m/s
The radius of the pizza dough, r=0.10 m
The mass of the pizza dough, m=0.50 kg
The centripetal force of an object is given by the equation,
[tex]F=m\frac{v^2}{r}[/tex]
On substituting the known values in the above equation,
[tex]\begin{gathered} F=0.50\times\frac{0.65^2}{0.10} \\ =2.11\text{ N} \end{gathered}[/tex]
Thus the centripetal force experienced by the pizza dough is 2.11 N
