Respuesta :
Given data:
Mass of block is,
[tex]m=50\text{ kg}[/tex]Force -1 is,
[tex]F_1=2.0\text{ N (towards left)}[/tex]Force-2 is,
[tex]F_2=12.0\text{ N (towards right)}[/tex]Assume that, direction towrds right is +x direction and direction towrds left is -x direction.
Formula of acceleration is as follows:
[tex]a=\frac{F_{net}}{m}\ldots(1)[/tex]Here,
[tex]F_{net}\text{ is net force applied on the block}[/tex]Now,
[tex]F_{net}=-F_1+F_2[/tex]Force-1 is negative. Because, direction of force-1 is towards left.
Hence,
[tex]\begin{gathered} F_{net}=-2.0\text{ N+12.0 N} \\ F_{net}=+10.0\text{ N} \end{gathered}[/tex]Now, substitute known values in equation-(1),
[tex]\begin{gathered} a=\frac{+10.0\text{ N}}{50\text{ kg}} \\ a=+0.2m/s^2 \end{gathered}[/tex]Here, +ve sign indicates that direction of acceleration is towards right
