We will solve as follows:
*We will use the law of sines to determine the value of beta, that is:
[tex]\frac{3}{\sin(\beta)}=\frac{5}{\sin (90)}[/tex]
Now, we solve for beta:
[tex]\Rightarrow\sin (\beta)=\frac{3\sin(90)}{5}\Rightarrow\sin (\beta)=\frac{3}{5}[/tex][tex]\Rightarrow\beta=\sin ^{-1}(\frac{3}{5})[/tex][tex]\Rightarrow\tan (\beta)=\frac{3}{4}[/tex]
