0.0156moles
According to the ideal gas equation:
[tex]PV=nRT[/tex]where;
• P is the ,pressure ,of the gas (in atm)
,• V is the ,volume ,of the gas (in L)
,• n is the number of moles
,• R is the ,Gas constant
,• T is the temperature (in K)
Given the following parameters
P = 1.56atm
V = 250mL = 0.25L
R = 0.0821 L. Atm/mol.k
T = 32 + 273 = 305K
Substitute the given parameters into the formula
[tex]\begin{gathered} n=\frac{PV}{RT} \\ n=\frac{1.56\times0.25}{0.0821\times305} \\ n=\frac{0.39}{25.04} \\ n=0.0156moles \\ \end{gathered}[/tex]Hence the required number of moles of N2 is 0.0156moles
