Given the figure of a cone inside a cylinder
The volume of the space between the cylinder and the cone = the volume of the cylinder - the volume of the cone
The volume of the cylinder =
[tex]\pi\cdot r^2\cdot h[/tex]
The volume of the cone =
[tex]\frac{1}{3}\cdot\pi\cdot r^2\cdot h[/tex]
So, the volume of the space between them =
[tex]\pi\cdot r^2\cdot h-\frac{1}{3}\pi\cdot r^2\cdot h=\frac{2}{3}\pi\cdot r^2\cdot h[/tex]
As shown in the figure: r = 4/2 = 2 in
h = 6 in
Let pi = 3.14
So, substitute with r, h, and pi
The volume of the space =
[tex]\frac{2}{3}\cdot3.14\cdot2^2\cdot6=50.24[/tex]
Rounding to the nearest whole number
So, the answer will be option B) 50 in^3
