Given:
Team X has a 40% chance of winning a game against team Y and team A has a 25% chance of winning a game against team B.
Required:
What is the probability of team X and team A winning their respective games?
Explanation:
The concept required:
[tex]Probability(P)=\frac{\text{ Number of favorable outcomes}}{\text{ Number of total outcomes}}[/tex]So,
[tex]\begin{gathered} P(X\text{ winning agianst }Y)=\frac{40}{100} \\ =\frac{2}{5} \end{gathered}[/tex]And
[tex]\begin{gathered} P(A\text{ winning against }B)=\frac{25}{100} \\ =\frac{1}{4} \end{gathered}[/tex]Answer:
Completed the answer.
