the Given data:
Initial volume;
[tex]V_1=130\operatorname{cm}^3[/tex]Initial pressure;
[tex]P_1=1\text{ atm}[/tex]Final volume;
[tex]V_2=40\operatorname{cm}^3[/tex]According to ideal gas equation;
[tex]PV=\text{constant}[/tex]Therefore,
[tex]P_1V_1=P_2V_2^{}[/tex]Here, P_2 is the final pressure.
The final pressure is given as,
[tex]P_2=\frac{P_1V_1}{V_2}[/tex]Substituting all known values,
[tex]\begin{gathered} P_2=\frac{(1\text{ atm})\times(130\operatorname{cm})}{(40\operatorname{cm}^3)} \\ =3.25\text{ atm} \end{gathered}[/tex]Therefore, the new pressure inside the pump is 3.25 atmospheres.
