Respuesta :

Solution

Using the pythagoras

[tex]\begin{gathered} x^=\sqrt{14^2+2^2} \\ x^=\sqrt{200} \\ x=10\sqrt{2} \end{gathered}[/tex]

The length of the common external tangent is

[tex]10\sqrt{2}=\text{ 14.14213}[/tex]

The final answer

[tex]\:14.14213[/tex]

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