Step 1:
Divide the figure into parallelogram, trapezium and a rectangle.
Step 2:
Find the area of each figure
Area of parallelogram A
[tex]\begin{gathered} \text{Area of parallelogram = Base }\times\text{ Height} \\ =\text{ 4 }\times\text{ 3} \\ =12in^2 \end{gathered}[/tex]
Area of rectangle B with dimension 18 in by 4 in
[tex]\begin{gathered} \text{Area of rectangle B = Length }\times\text{ Breadth} \\ =\text{ 18 }\times\text{ 4} \\ =72in^2 \end{gathered}[/tex]
Find the area of trapezium C
[tex]\begin{gathered} \text{Area of trapezium = }\frac{1}{2}(a\text{ + b)}\times h\text{ } \\ \text{a = 1 , b = 2 , h = 4} \\ \text{Area of trapezium = }\frac{1}{2}(1\text{ + 2)}\times4\text{ } \\ \text{Area of trapezium = }\frac{12}{2}\text{ } \\ \text{Area of trapezium = }6in^2 \end{gathered}[/tex]
Final answer
The area of the figure is the sum of the area of the trapezium, parallelogram and rectangle.
= 6 + 72 + 12
= 90
