Solution
Step 1
Write the expression
[tex]\frac{x^2-13x\text{ + 40}}{x^2-25}\text{ }\times\text{ }\frac{x^2+6x+5}{x^2-7x-8}[/tex]
Step 2:
[tex]\begin{gathered} \frac{x^2-8x-5x+40}{(x-5)(x+5)}\text{ }\times\text{ }\frac{x^2+x\text{ +5x+5}}{x^2+x\text{ -8x - 8}} \\ \frac{(x-8)(x-5)}{(x-5)(x+5)}\text{ }\times\text{ }\frac{(x+1)(x+5)}{(x+1)(x-8)} \\ 1 \end{gathered}[/tex]
Final answer
1
