PercivalG97598 PercivalG97598

27-10-2022
Mathematics

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How many solutions does the following function have? 2x^2-3x+1=0

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LaitynK504675 LaitynK504675

27-10-2022

The given expression is

[tex]2x^2-3x+1=0[/tex]

Let's use the discriminant to know the number of solutions.

[tex]b^2-4ac[/tex]

Where a = 2, b = -3, and c = 1.

[tex](-3)^2-4\cdot2\cdot1=9-8=1[/tex]

This means the equation has two real solutions.

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