Given that the length of one of the sides of the triangle is the radius, the length of the other leg of the triangle is also 6 units.
Therefore, this is an instance of a 45-45-90 triangle. The value of x can now be solve by
Given that the side length of the 45-45-90 triangle is 6 units, the length of the hypotenuse x is
[tex]x=6\sqrt[]{2}[/tex]
