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That AAB that event that randomly selected RSC student has an associated art student and PAA equals 0.39. let the event PM be the event that a randomly selected arrest student is on the pre med degree track and PPM equals 0 to 6 point finally the probability that a randomly selected area student is an AA degree seeker and on the premium degree track in 0.05 used this information to calculate the following probability

Respuesta :

we are asked to determine the probability of one or another event happening. This can be calculated with "Or" rule for probability, that is:

[tex]P(\text{AorB)}=P(A)+P(B)-P(\text{AandB)}[/tex]

Replacing for AA and PM probabilities we get:

[tex]P(\text{ AAorPM)=P(AA)+P(PM)}[/tex]

Replacing the probabilities:

[tex]P(\text{ AAorPM)=}0.39+0.26-0.05[/tex]

Solving the operations:

[tex]P(\text{ AAorPM)=}0.6[/tex]

Therefore, the probability is 0.6.

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