$4500 is deposited for 4.5 years in an account that pays 4.5% interest compounded monthly. What is the value of the account when the customer takes the money at the end of the 4.5 years?

Respuesta :

Answer:

$5507.98

Explanation:

To find the value of the account, we use the compound interest formula below:

[tex]Amount\: at\: Compound\: Interest,A=P(1+\frac{r}{n})^{nt}[/tex]

From the given information:

• Principal,P=$4500

,

• Interest Rate, r=4.5%=0.045

,

• Number of compounding periods, n=12 (Monthly)

,

• Time, t=4.5 years

Substituting the given values, we have:

[tex]\begin{gathered} A=4500(1+\frac{0.045}{12})^{12\times4.5} \\ =4500(1+0.00375)^{54} \\ =4500(1.00375)^{54} \\ =\$5507.98 \end{gathered}[/tex]

The value of the account when the customer takes the money at the end of the 4.5 years is $5507.98.