Respuesta :
Answer: 74.43%
Let us first list down the probabilities of the machine working.
First is the probability that none of the components will fail. We can write this probability as:
[tex]P(0)=(1-0.3)^6[/tex]Next, the probability that one of the components will fail. This will give us:
[tex]P(1)=C^1_6(1-0.3)^5(0.3)[/tex]Then, the probability that 2 of the components will fail.
[tex]P(2)=C^2_6(1-0.3)^4(0.3)^2[/tex]Adding all of these probabilities and we will have:
[tex]P=(1-0.3)^6+C^1_6(1-0.3)^5(0.3)+C^2_6(1-0.3)^4(0.3)^2[/tex][tex]P=(0.7)^6+(6)(0.7)^5(0.3)+(15)(0.7)^4(0.3)^2[/tex][tex]P=0.74431\times100=74.43\%[/tex]Therefore, the probability that the machine will be working would be 74.43%.
