5.
(x + 1)^2 + 3
x^2 + 2x + 1 + 3
x^2 + 2x + 4
To find the vertex (h,k)
h = -b/2a = -2/(2*1) = -1
k = f(-1) = x^2 + 2x + 4 = 3
Vertex = (-1, 3)
6.
(x + 1)^2 + 4
x^2 + 2x + 5
h = -2/(2*1) = -1
k = f(-1) = x^2 + 2x + 5 = 4
Vertex = (-1, 4)
7.
(x + 1)^2 + 6
x^2 + 2x + 7
h = -2/(2*1) = -1
k = f(-1) = x^2 + 2x + 7 = 6
Vertex = (-1, 6)
