a stadium has a section 15cm in length,12m in width and 3m in height. how many people can it hold if each person requires 6 M3 of air space?

The volume of a rectangular prism can be calculated using this formula:
[tex]V_r=l\cdot w\cdot h[/tex]Where "l" is the length, "w" is the width and "h" is the height.
In this case, you know that the dimensions of the section are:
[tex]\begin{gathered} l=15m \\ w=12m \\ h=3m \end{gathered}[/tex]Therefore, substituting values into the formula and evaluating, you get that its volume is:
[tex]V_{\text{section}}=(15\operatorname{cm})(12m)(3m)=540m^3[/tex]According to the explanation given in the exercise, each person requires this volume of air space:
[tex]V_{\text{air}}=6m^3[/tex]Then, to find the number of people it can hold, you need to set up that:
[tex]Number\text{ }of\text{ }people=\frac{V_{\text{section}}}{\text{V}_{\text{air}}}[/tex]Hence, you get:
[tex]Number\text{ }of\text{ }people=\frac{540m^3}{6m^3}=90[/tex]Therefore, the answer is: 90 people.