Respuesta :

So based on the problem:

2*mech= elec

3*mech= chem

And the sum of all is 1200

[tex]\begin{gathered} 1200=e+c+m \\ e=2m \\ c=3m \\ 1200=2m+3m+m=6m \\ \frac{1200}{6}=m=200 \end{gathered}[/tex]

The answer is the first option

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