The initial speed = 25.16 m/s
Explanation:The maximum height, H = 32.3 m
The initial speed, u = ?
The formula for the maximum height of a projectile is:
[tex]H=\frac{u^2}{2g}[/tex]Substitute H = 32.3m and g = 9.8 m/s² into the formula and solve for u
[tex]\begin{gathered} 32.3=\frac{u^2}{2(9.8)} \\ \\ u^2=32.3(2)(9.8) \\ \\ u^2=633.08 \\ \\ u=\sqrt{633.08} \\ \\ u=25.16\text{ m/s} \end{gathered}[/tex]The initial speed = 25.16 m/s
