The surface area of a box with length L, width W, and height H is given by: box wi
[tex]S.A.=2(L\cdot W+L\cdot H+W\cdot H)[/tex]
From the problem, we identify:
[tex]\begin{gathered} L=3\text{ yd} \\ W=3\text{ yd} \\ H=3\text{ yd} \end{gathered}[/tex]
Then, using the formula:
[tex]\begin{gathered} S.A.=2(3\cdot3+3\cdot3+3\cdot3)=2(9+9+9)=2(27) \\ \\ \therefore S.A.=54\text{ yd}^2 \end{gathered}[/tex]
