Respuesta :

[tex]\begin{gathered} m=\frac{-2}{3} \\ P(3,6) \\ y=mx+b \\ U\sin g\text{ the given data} \\ y=\frac{-2}{3}x+b \\ 6=\frac{-2}{3}(3)+b \\ 6=-2+b \\ b=6+2 \\ b=8 \\ Hence \\ \text{The equation of the line is }y=\frac{-2}{3}x+8 \end{gathered}[/tex]

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