[tex]\frac{3}{8}x-6=\frac{1}{2}(4-x)[/tex][tex]\begin{gathered} \frac{3x}{8}-6=2-\frac{x}{2} \\ \frac{3x}{8}+\frac{x}{2}=2+6 \\ \frac{6x+8x}{16}=8 \\ \frac{14x}{16}=8 \\ \frac{7x}{8}=8 \\ 7x=64 \\ x=\frac{64}{7} \end{gathered}[/tex]
This equation only has one solution. One would say this because x has exponent 1, and the comprobation is above.
