The times to complete an obstacle course is normally distributed with mean 73 seconds and standard deviation 9seconds. What is the probability using the Empirical Rule that a rana mly selected finishing time is less than 100seconds?• Provide the final answer as a percent rounded to two decimal places.

The times to complete an obstacle course is normally distributed with mean 73 seconds and standard deviation 9seconds What is the probability using the Empirica class=

Respuesta :

From empirical probability,

[tex]\begin{gathered} Z-\text{score = }\frac{X-\mu}{\sigma} \\ =\frac{100-73}{9} \\ =3 \\ \text{That means 100=}\mu+3\sigma \end{gathered}[/tex]

The percentage of the distribution that lies between 0 to 100 is

[tex]\begin{gathered} The\text{ percentage probability of distribution that lie between }\mu+3\sigma\text{ and }\mu-3\sigma\text{ plus } \\ \text{percentage of distribution that lie between 0 and }\mu-3\sigma \\ \end{gathered}[/tex][tex]\begin{gathered} =\text{ 99.7 + }\frac{100-99.7}{2} \\ =99.7\text{ + 0.15} \\ =99.85\text{ \% (2 decimal places)} \end{gathered}[/tex]