we have the functions
[tex]\begin{gathered} f(x)=\sqrt[3]{3x} \\ g(x)=3x+2 \end{gathered}[/tex]
Find out (f/g)(x)
[tex](\frac{f}{g})(x)=\frac{f(x)}{g(x)}=\frac{\sqrt[3]{3x}}{3x+2}[/tex]
Find out the restrictions
Remember that the denominator cannot be equal to zero
so
3x+2=0
3x=-2
x=-2/3
so
The value of x cannot be equal to x=-2/3
therefore
The answer is the option B
