10.39tons
The force exerted on the two tugboats F1 = F2 = 6tons
According to the cosine rule;
[tex]R^2=F_1^2+F_2^2+2F_1F_2cos\theta[/tex]where
R is the resultant force
theta is the angle between the two ropes
Substitute the given parameters
[tex]\begin{gathered} R^2=6^2+6^2+2(6)(6)cos60^0 \\ R^2=72+72cos60^0 \\ R^2=72+72(0.5) \\ R^2=72+36 \\ R^2=108 \\ R=\sqrt{108} \\ R=10.39tons \end{gathered}[/tex]Therefore the resultant force on the ship is 10.39tons
