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triangle JKM with side j across from angle J, side k across from angle K, and side m across from angle MIf m is 21 inches, k is 34 inches, and ∠J measures 60°, then find j using the Law of Cosines. Round your answer to the nearest tenth. 25.6 in 29.7 in 659 in 883 in

Respuesta :

Applying the law of cosines

we have that

[tex]j^2=m^2+k^2-2(m)(k)cos(J)[/tex]

substitute given values

[tex]\begin{gathered} j^2=21^2+34^2-2(21)(34)cos(60^o) \\ j^2=883 \\ j=29.7\text{ in} \end{gathered}[/tex]

The answer is 29.7 inches