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The gas in hairspray can I write a temperature of 303K in a pressure of 130 for K PA if the gas is in the can reach of pressure of 93 point4K PA can we explore to what temperature must gases be raised in order for the cans explode?

Respuesta :

this problem can be solved using the Gay lussacs law:

[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]

From the text we have the following information:

P1=134 kPa

T1=303K

P2= 93.4kPa

And they ask for T2, Then we just have to solve for T2 ans use the provided data:

[tex]T_2=\frac{T_1P_2}{P_1}=\frac{303K\cdot93.4kPa}{134kPa}=211.20K[/tex]

The can would explode at 211.20K

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