Given
Hears the echo at , t=0.250 s
Speed pf sound is v=340 m/s
To find
The distance from the wall
Explanation
let her distance from the wall be d.
When she hears the echo, the sound has travelled the same distance twice
So
[tex]\begin{gathered} v=\frac{2d}{t} \\ \Rightarrow340=\frac{2d}{0.250} \\ \Rightarrow d=d=42.5\text{ m} \end{gathered}[/tex]Conclusion
The distance of the wall from her is 42.5 m