Given:
[tex](x,y)=(2,-\sqrt[]{5})[/tex][tex]\begin{gathered} r=\sqrt[]{x^2+y^2} \\ r=\sqrt[]{(2)^2+(-\sqrt[]{5})^2} \\ r=\sqrt[]{4+5} \\ r=\sqrt[]{9} \\ r=3 \end{gathered}[/tex][tex]\begin{gathered} \cos \theta=\frac{x}{r} \\ =\frac{2}{3} \end{gathered}[/tex][tex]\begin{gathered} \csc \theta=\frac{r}{y} \\ =\frac{3}{-\sqrt[]{5}} \\ =-\frac{3}{\sqrt[]{5}} \end{gathered}[/tex][tex]\begin{gathered} \tan \theta=\frac{-\frac{\sqrt[]{5}}{3}}{\frac{2}{3}} \\ =-\frac{\sqrt[]{5}}{2} \end{gathered}[/tex]
