Respuesta :

Answer:

(y + 3)(y - 6)

Explanations:

The given quadratic expression is:

[tex]y^2-3y-18[/tex]

Multiply the coefficient of y² and the last term

1 x 18 = 18

Look for factors of 18 that can add up to the middle term. That is, -6 and 3

Therefore, instead of writing -3y at the middle as it is in the expression, you write -6y + 3y

The given expression therefore becomes:

[tex]y^2-6y+3y-18[/tex]

Factorise the common factors of the first two and the last two terms

[tex]y(y-6)+3(y-6)[/tex]

The expression finally becomes:

(y + 3) (y - 6)