The given equation is
1)
[tex]4x^2+20x+24=0^{}_{}[/tex]
Divide by 4, we get
[tex]x^2+5x+6=0^{}_{}[/tex]
[tex]x^2+3x+2x+6=0^{}_{}[/tex]
[tex]x(x^{}+3)+2(x+3)=0^{}_{}[/tex]
[tex](x+3)(x+2)=0[/tex]
By factoring in this equation. we can find a solution
Hence here the answer is
Factor the equation
2)
The given equation is
[tex]3x^2+30x=24[/tex]
Divide by 3, we get
[tex]x^2+10x=8[/tex]
[tex]x^2+10x-8=0[/tex]
[tex]x^2+10x+25-25-8=0[/tex]
[tex](x-5)^2-33=0[/tex]
[tex](x-5)^2=33[/tex]
[tex]x-5=\pm\sqrt[]{33}[/tex]
[tex]x=\pm\sqrt[]{33}+5[/tex]
Hence we solved by using completing the square.
For this answer is
Complete the square.
3)
The given equation is
[tex]x^2+5x+2=0[/tex]
We are not able to factor this equation.
We need to use the quadratic formula to solve this quadratic equation.
Fo this the answer is
Use the quadratic formula
