We will solve as follows:
We graph each line as follows:
*First, we calculate the x & y-intercept points of each line, those are found by replacing y= 0 & x = 0 respectively:
+Line 1:
[tex]o=7x-3\Rightarrow7x=3\Rightarrow x=\frac{3}{7}[/tex]
Its y-intercept is located at the point (3/7, 0)
[tex]y=7(0)-3\Rightarrow y=-3[/tex]
Its x-intercept is located at the point (0, -3).
+Line 2:
[tex]0=x+3\Rightarrow x=-3[/tex]
Its y-intercept is located at the point (-3, 0).
[tex]y=(0)+3\Rightarrow y=3[/tex]
Its x-intercept is located at the point (0, 3).
**Now, using the x & y-intercepts of each line we plot the line using those points, as shown:
***
Since 3/7 is an irrational number it cannot be plotted by hand perfectly, so you can use another point of the line [Replace a value for y such that a solution is a number that can be plotted perfectly by hand] or you can use software to plot that point. I'll show you another point to plot it:
We can use y = 11 and we will get x = 2 (That is another point of the line that can be used to plot the line) [We use the x & y-intercepts since they are the immediate solutions most of the time, but any two points of the line can be used to plot it]. Look at the other point being used to plot it:
