A lake was stocked with 380 trout. Each year, the population decreases by 20. The population of trout in the lake after x years is represented by the function f(x)=380-20x.

x-intercept = -19
y-intercept = 380
Given
[tex]f(x)=380-20x[/tex]Part A
To find the x-intercept, we set y=0
The x intercept is the point where the line crosses the x axis. At this point y = 0
[tex]\begin{gathered} y=380-20x \\ \text{when y=0 what is x } \\ 0=380-20x \\ 380=-20x \\ \text{rewrite} \\ -20x=380 \\ \text{divide both sides by -20} \\ -\frac{20x}{20}=\frac{380}{-20} \\ \\ x=-19 \end{gathered}[/tex]Part B
To find the y-intercept, we set x=0
The y- intercept is the point where the line crosses the x-axis.
At this point x= 0
[tex]\begin{gathered} y=380-20x \\ x=0 \\ y=380-20(0) \\ y=380-0 \\ y=380 \end{gathered}[/tex]Part C
Graph of f(x)=380-20x