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A baseball "diamond is actually a square with side lengths of 90 feet. In a game, a runner tries to steal second base. How far must the catcher throw from home plate to second base in order to get the runner out? O 90V2 feet 0 903 feet O 90 feet 180 feet

A baseball diamond is actually a square with side lengths of 90 feet In a game a runner tries to steal second base How far must the catcher throw from home plat class=

Respuesta :

From the given figure we have a square with a side length of 90 feet

The distance of thrown represents the diagonal of the square

The relation between the diagonal (d) of the square and its side (s) is

[tex]d=s\sqrt[]{2}[/tex]

Since

feet, then

[tex]d=90\sqrt[]{2}feet[/tex]

The answer is A

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