[tex]\begin{gathered} A=\frac{r^2}{2}\theta \\ \text{Where:} \\ A=\text{Area of the circular sector}=67m^2 \\ \theta=angleinradians=100^{\circ}\times\frac{\pi}{180}=\frac{5}{9}\pi \\ \end{gathered}[/tex]
Solving for r:
[tex]\begin{gathered} 67=\frac{r^2}{2}\frac{5}{9}\pi \\ r^2=\frac{67\times18}{5\pi} \\ r=\pm\sqrt[]{76.77634455} \\ r=\pm8.762211168 \\ r\approx8.8 \end{gathered}[/tex]
