The given quadratic can be solved bt completing the square as,
[tex]\begin{gathered} x^2-6x-5=0 \\ x^2-2(3)x+3^2-3^2-5=0 \\ (x-3)^2=14 \\ x-3=\pm\sqrt[]{14} \\ x=3\pm\sqrt[]{\text{ 14}} \\ x=3\pm3.74 \\ x=6.74,-0.74 \end{gathered}[/tex]
Thus, the above values are the solution.
