Notice that 5*5=25, and 6*6=36; thus,
[tex]\Rightarrow\sqrt[]{25}=5,\sqrt[]{36}=6[/tex]
Furthermore,
[tex]\begin{gathered} \sqrt[]{25}<\sqrt[]{28}<\sqrt[]{36} \\ \Rightarrow5<\sqrt[]{28}<6 \end{gathered}[/tex]
Thus, sqrt(28) is between 5 and 6, the answer is the third option (top to bottom)
It is a fact that
[tex]\begin{gathered} b>a\ge0 \\ \Rightarrow\sqrt[]{b}>\sqrt[]{a} \end{gathered}[/tex]
