The smallest possible number of students in the algebra class is 13.
Let n≥5 be the number of students.
The sum of their scores must be at least 5×100 + (n - 5).
Simultaneously, we must achieve the mean 76, which is equivalent to achieving the mean sum 76n.
As a result, we have a sufficient precondition on n: we should have 5×100 + (n - 5) ≤ 76n.
This can be reduced to 200 ≤ 16n. This is true for the smallest integer n = 13.
To complete our solution, we must now determine how 13 students might have scored just on test.
We have 13×76 = 988 points to distribute to them. Because five 100s equal 500, we must distribute the remaining 488 points as among remaining eight students.
This can be accomplished, for example, by awarding each of them 61 points.
Thus, the smallest possible number of students in the class is 13.
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